A manufacturing department has three machines. On a given day the production was as follows…

Q 1: A manufacturing department has three machines. On a given day the production was as follows. Machine 1 produced 200 items in 8 hours. Machine 2 produced 150 items in 6 hours. Machine 3 produced 160 items in 7 hours. What was the overall productivity of the manufacturing department? Answer: 24.29 units/hour Solution Total Items produced = 200+150+160 = 510 Total Hours = 21 Productivity = 510/21 = 24.29 units/hour.

Don't use plagiarized sources. Get Your Custom Essay on
A manufacturing department has three machines. On a given day the production was as follows…
Just from $13/Page
Order Essay

Document Preview:

Page 1 of 4 Sample Examination Questions Question on Productivity Q 1: A manufacturing department has three machines. On a given day the production was as follows. Machine 1 produced 200 items in 8 hours. Machine 2 produced 150 items in 6 hours. Machine 3 produced 160 items in 7 hours. What was the overall productivity of the manufacturing department? Answer: 24.29 units/hour Solution Total Items produced = 200+150+160 = 510 Total Hours = 21 Productivity = 510/21 = 24.29 units/hour.
Page 2 of 4 Sample Examination Questions Questions on Forecasting Table 1 Month 1 2 3 4 5 6 7 8 9 10 11 12 Actual Demand 6916 6719 6029 7336 7053 7753 6789 6352 6005 7190 6459 6928 FCT 1: Find the forecast for month 8 using four month moving average based on the data given in Table 1. Answer: 7232.75 Solution = (7336+7053+7753+6789)/4 FCT-2: Compute a weighted 4 month moving average for month 7 by using the following weights: 0.4, 0.3, 0.2 and 0.1. The weight is the highest for the latest month. Use the data given in Table 1. Answer: 7287.20 Solution = 0.1*6029+0.2*7336+0.3*7053+0.4*7753 FCT-3: Find the forecast for month 3 by using exponential smoothing with a = 0.3. Use the data given in Table 1. Answer: 6856.90 6856.90 Solution: Set Forecast of Month 1= Demand for Month 1 = 6916 Then find forecast for month 2 = 6916 + 0.3*(6916-6916) = 6916 Forecast for month 3 = 6916+0.3*(6719-6916) = 6856.90 Table 2 Month 1 2 3 4 5 6 7 8 9 10 11 12 Actual Demand 6916.00 6719.00 6029.00 7336.00 7053.00 7753.00 6789.00 6352.00 6005.00 7190.00 6459.00 6928.00 Forecast 6228.00 7651.00 6800.00 6675.00 6493.00 7841.00 6962.00 7613.00 7505.00 6103.00 6740.00 7809.00 FCT-4: Find the value of Mean Absolute Deviation (MAD) at the end of month 8 based on the data given in Table 2. Answer: 641.75 Solution: Find the absolute value of error for months 1 through 8. Cumulative sum of absolute errors form months 1 through 8 = 5134.00 MAD = 5134/8 = 641.75 FCT-5: Find the value of the tracking signal at the end of…

Attachments:

Leave a Reply

Your email address will not be published. Required fields are marked *

*

*

*